Question #a59cd

1 Answer
Sanjay VN
Jan 15, 2018

is 0

Explanation:

so
log10^x = log5^(2x)
log10^x - log5^(2x)=0
which is
log(10^x/5^(2x))=0
log((2*5)^x/(5^x*5^x))=0
log(2^x/5^x)=0
hence
(2/5)^x = 1
so
2^x = 5^x
which is never possible for any value other than
x=0
therefore solution is x=0
hope u find it helpful :)

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