Points A and B are at (3 ,7 )(3,7) and (4 ,2 )(4,2), respectively. Point A is rotated counterclockwise about the origin by pi π and dilated about point C by a factor of 5 5. If point A is now at point B, what are the coordinates of point C?

2 Answers
Jan 13, 2018

After Point A is rotated counterclockwise about the origin by piπ, its new coordinates are (-3, -7)(3,7).

The difference between the xx coordinates of Point A and B now is 4-(-3)=74(3)=7 and yy coordinates: 2-(-7)=92(7)=9

Since Point A was dilated about Point C by a factor of 5, we can find out by how much the coordinates change with each integer increase in factor.

For the xx coordinate:
7/4=1.7574=1.75
and yy coordinate:
9/4=2.2594=2.25

So for every integer increase in factor, the point moves 1.75 to the right and 2.25 upwards.

Point C is therefore
(-3-1.75, -7-2.25)(31.75,72.25)
=(-4.75, -9.25)=(4.75,9.25)

Jan 13, 2018

C=(-19/4,-37/4)C=(194,374)

Explanation:

"under a counterclockwise rotation about the origin of "piunder a counterclockwise rotation about the origin of π

• " a point "(x,y)to(-x,-y) a point (x,y)(x,y)

rArrA(3,7)toA'(-3,-7)" where A' is the image of A"

rArrvec(CB)=color(red)(5)vec(CA')

rArrulb-ulc=5(ula'-ulc)

rArrulb-ulc=5ula'-5ulc

rArr4ulc=5ula'-ulb

color(white)(4ulcxx)=5((-3),(-7))-((4),(2))

color(white)(xxxx)=((-15),(-35))-((4),(2))=((-19),(-37))

rArrulc=1/4((-19),(-37))=((-19/4),(-37/4))

rArrC=(-19/4,-37/4)