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Answer 1 · 2018-01-11T20:28:51

$please see the fallowing details.$ $"please see the fallowing details."$

We firstly should remember the law of Coulomb.
Coulomb's law states that electrical charges apply electrical force to each other.
$F = k \cdot \frac{q_{1} \cdot q_{2}}{r^{2}}$ $F=k*(q_1*q_2)/(r^2)$
$where ; q_{1}, q_{2} are charges,$ $"where ; "q_1,q_2 " are charges,"$
$r distance between q_{1} and q$ $"r distance between " q_1 and q_"$
$k : constant.$ $k:"constant."$
If the electrical charges have the same sign , then electrical charges push each other.
If the electrical charges have the opposite sign , then electrical charges pull each other.
The magnitude of the force exerted by A on B has shown in figure.

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The magnitude of the force acted by B on A is the same but this force has opposite direction.

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