Cos theta + sin theta times tan theta = 2, theta= ?

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Answer 1 · 2018-01-11T03:41:06

#60^@#

#costheta + sintheta*tantheta = 2#

as, #tantheta = sintheta/costheta#

#costheta + sin^2theta/costheta = 2#

#:. (cos^2theta + sin^2theta)/costheta = 2#

as, #sin^2theta + cos^2theta = 1#

#costheta = 1/2#

#:. theta = 60^@#

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