Question #e528f

1 Answer
Brandon
Jan 10, 2018

#color(blue)(3(x-2y)#

Explanation:

1) Find out what is common between both expressions, (can be either a number or a letter, for example x or y in this instance).
Both expressions have a multiple of #3#, and no letter so therefore this goes outside the bracket

#color(red)(3(...-...)# There is a minus in the middle as it is #-6y#.

2) then you figure out what #3# multiplies by to get #3x# and what #3# multiplies by to get #6y#.

#color(red)(3*x=3x#
#color(red)(3*2y=6y#

#therefore# Both of these go inside the bracket to make...

#color(blue)(3(x-2y)#

Related questions
Impact of this question
242 views around the world
You can reuse this answer
Creative Commons License