A circle has a diameter of 16 inches. What is the area of the circle to the nearest square inch?

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A circle has a diameter of 16 inches. What is the area of the circle to the nearest square inch?

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Answer 1 · 2018-01-09T15:50:35

$201$ $201$ square inches

Explanation:

Area of a circle, $A$ $A$ = $π r^{2}$ $pir^2$
$r$ $r$ = radius of the circle = $\frac{d i a m e t e r}{2}$ $(diameter)/2$ = $\frac{16}{2}$ $16/2$ = $8$ $8$ inches

So, area of circle = $π \times 8^{2}$ $pixx8^2$ = $\frac{22}{7} \times 8^{2}$ $22/7xx8^2$ = $\frac{1408}{7}$ $1408/7$ = $201.14$ $201.14$ square inches

(Note: $π$ $pi$ = $\frac{22}{7}$ $22/7$ )

So, are of the circle to nearest square inches = $201$ $201$ square inches

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A circle has a diameter of 16 inches. What is the area of the circle to the nearest square inch?

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