The vertices of triangle ABC are A(-2, 2), B(6, 2), and C(0, 8). What is its perimeter?

1 Answer
Parabola
Jan 8, 2018

#8+6sqrt2+2sqrt10#

Explanation:

We are essentially finding the distance between these points, and then add them up.
Remember the distance formula:#d=sqrt ((x_2-x_1)^2+(y_2-y_1)^2)#

The distance from points A to B is:
#d=sqrt ((6-(-2))^2+(2-2)^2)#
#d=sqrt (64+0)#
#d=8#

The distance from points B to C is:
#d=sqrt ((0-6)^2+(8-2)^2)#
#d=sqrt (36+36)#
#d=sqrt 72#
#d=6sqrt 2#

The distance from points A to C is:
#d=sqrt ((0-(-2))^2+(8-2)^2)#
#d=sqrt (4+36)#
#d=sqrt 40#
#d=2sqrt 10#

We add'em up.
#8+6sqrt2+2sqrt10# That is your answer!

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