How do you solve #6k + 5= 2k + 1#?

2 Answers
smendyka
Jan 8, 2018

See a solution process below:

Explanation:

First, subtract #color(red)(5)# and #color(blue)(2k)# from each side of the equation to isolate the #k# term while keeping the equation balanced:

#6k - color(blue)(2k) + 5 - color(red)(5) = 2k - color(blue)(2k) + 1 - color(red)(5)#

#(6 - color(blue)(2))k + 0 = 0 - 4#

#4k = -4#

Next, divide each side of the equation by #color(red)(4)# to solve for #k# while keeping the equation balanced:

#(4k)/color(red)(4) = -4/color(red)(4)#

#(color(red)(cancel(color(black)(4)))k)/cancel(color(red)(4)) = -1#

#k = -1#

LucaGasparro
Jan 8, 2018

Just a simple linear equation.
#k=-1#

Explanation:

To solve we must solve like any other linear equation. To do this we must get all variables, in this case the k's, on one side and all the of the constants on the other side.

#therefore# #6k+5 = 2k+1#
#therefore# #4k = -4#

Now to find #k# we just divide by the coefficient, in this case #4#

#therefore k=-1#

Related questions
Impact of this question
1785 views around the world
You can reuse this answer
Creative Commons License