What is the area of a rectangle with sides of #(3x +6)# and #2x-5#?

1 Answer
Brandon · Parabola
Jan 7, 2018

#6x^2-3x-30#

Explanation:

Remember that the area of a rectangle is its length times its width.
Multiply #(3x+6)# and #(2x-5)#
#A=(3x+6)(2x-5)#

Use the FOIL:(Front, Outer, Inner, Last)
#3x*2x=6x^2#
#3x*-5=-15x#
#6*2x=12x#
#6*-5=-30#
We essentially add these terms.
Collecting like terms gets us the result of:
#6x^2-3x-30#

So therefore the are is #6x^2-3x-30# for a given value of x.

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