What is the area of a rectangle with sides of (3x +6) and 2x-5?

1 Answer
Brandon ยท Parabola
Jan 7, 2018

6x^2-3x-30

Explanation:

Remember that the area of a rectangle is its length times its width.
Multiply (3x+6) and (2x-5)
A=(3x+6)(2x-5)

Use the FOIL:(Front, Outer, Inner, Last)
3x*2x=6x^2
3x*-5=-15x
6*2x=12x
6*-5=-30
We essentially add these terms.
Collecting like terms gets us the result of:
6x^2-3x-30

So therefore the are is 6x^2-3x-30 for a given value of x.

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