Question #a9f26

1 Answer
Parabola
Jan 7, 2018

f'(x)=-(cot(sqrtx)csc(sqrtx))/(2sqrtx)

Explanation:

Let's assume that you meant f'(x) instead of f^!(x).
We use chain rule and then power rule for this problem.

First, remember that the derivitive of f(x)=csc(x) is -cot(x)csc(x)
MAKE SURE YOU UNDERSTAND WHY!

Also, remember that if f(x)=x^y, then f'(x)=yx^(y-1)

Therefore, f'(x)=-cot(sqrtx)csc(sqrtx)*1/2x^-(1/2) or f'(x)=-(cot(sqrtx)csc(sqrtx))/(2sqrtx)

Related questions
Impact of this question
958 views around the world
You can reuse this answer
Creative Commons License