What is the domain and range of f(x) =sqrt(28.5 − 3 x)?

1 Answer
Jan 5, 2018

Domain: (-oo, 9.5]
Range: [0, +oo)

Explanation:

The condition of existence of a square root is satisfied for the radicand\ge 0.

So let's solve:
28.5 - 3x \ge 0
- 3x \ge -28.5
3x \le 28.5
\frac{3}{3}x \le \frac{28.5}{3}
x \le 9.5

Domain: (-oo, 9.5]

While the range is positive for every x \in (-oo, 9.5] that you put in f(x).

Range: [0, +oo)

graph{sqrt(28.5-3x) [-2.606, 11.44, -0.987, 6.04]}