Question #95196

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Question #95196

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Answer 1 · 2018-01-03T18:28:20

Larger number is $37$ $37$ and smaller number is $26$ $26$

Explanation:

Suppose the smaller number is $x$ $x$
and, the larger number is $x + 11$ $x+11$

Now, its given that: $x + 11$ $x+11$ + $5 x$ $5x$ = $167$ $167$ .....(1)

Solving for $x$ $x$ , Equation (1) can be written as:

$6 x + 11$ $6x+11$ = $167$ $167$

or, $6 x$ $6x$ = $167 - 11$ $167-11$ = $156$ $156$

or, $x$ $x$ = $cancel156^26/cancel6^1$ = $26$

Therfore, the larger number will be $x+11$ = $26+11$ = $37$

Answer 2 · 2018-01-03T18:33:43

$37" and "26$

Explanation:

$"let the smaller number "=x$

$"then the larger number "=x+11$

$rArrx+11+5x=167larrcolor(blue)"solve for x"$

$rArr6x+11=167$

$"subtract 11 from both sides"$

$6xcancel(+11)cancel(-11)=167-11$

$rArr6x=156$

$"divide both sides by 6"$

$(cancel(6) x)/cancel(6)=156/6$

$rArrx=26$

$"smaller number "=x=26$

$"larger number "=x+11=26+11=37$

$color(blue)"As a check"$

$37+(5xx26)=37+130=167larr"True"$

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Question #95196

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