How do you solve #-[ 3x + ( 5x + 3) ] = 9- ( 6x + 1)#?

1 Answer
Alex C.
Jan 3, 2018

#x=-\frac{11}{2}#

Explanation:

#-[3x+(5x+3)]=9-(6x+1)#

The first round brackets are preceded by the #+# sign, so they can be removed leaving the sign of the contained terms unchanged:
#-[3x+5x+3]=9-(6x+1)#

While for those preceded by the #-# we must invert the signs of terms:
#-[3x+5x+3]=9-6x-1#

Same reasoning for square brackets (#-# sign before):
#-3x-5x-3=9-6x-1#

Now let's move all the terms from the second part to the first part of equation changing the sign
#-3x-5x-3-9+6x+1=0#

Sum all terms with the #x# togheter and all the constants (terms whitout #x# toghter:
#-2x-11=0#

Move #-11# to the other side by changing the sign
#-2x=11#

Multiply both sides by #-1# to change the sign (the term x should be positive for readability):
#2x=-11#

Final result:
#x=-\frac{11}{2}#

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