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Answer 1 · 2018-01-02T17:10:15

$306 s q . c m$ $306 sq. cm$

When sides of a triangle are given, use Heron's formula to find the area of the triangle.

Area = $\sqrt{p (p - a) (p - b) (p - c)}$ $sqrt(p(p-a)(p-b)(p-c)$

Where, $p$ $p$ = $\frac{a + b + c}{2}$ $(a+b+c)/2$

and, $a, b, c$ $a, b, c$ are sides of the triangle.

Therefore, $p$ $p$ = $\frac{51 + 37 + 20}{2}$ $(51+37+20)/2$ = $54 c m$ $54 cm$

and, Area = $\sqrt{54 \times (54 - 51) \times (54 - 37) \times (54 - 20)}$ $sqrt(54xx(54-51)xx(54-37)xx(54-20)$

= $\sqrt{54 \times 3 \times 17 \times 34}$ $sqrt(54xx3xx17xx34$ = $306 s q . c m$ $306 sq. cm$