Question #48746

1 Answer
Timber Lin
Dec 29, 2017

They are reciprocals.

Explanation:

By using change of base, #log_k(m)=ln(m)/ln(k)# and #log_m(k)=ln(k)/ln(m)#.

You can see that #ln(m)/ln(k)# and #ln(k)/ln(m)# are reciprocals, meaning #log_k(m)# and #log_m(k)# are also reciprocals.

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