Question #dc056

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Question #dc056

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Answer 1 · 2017-12-28T20:50:16

25

Explanation:

Its given that $x + y = x y = 5$ $x+y = xy = 5$
Now, to solve the given equation which is:
$x^{2} y + y^{2} x = ? ? ? ?$ $x^2y+y^2x = ????$

This equation can also be written as:
$x \times x \times y$ $x xx x xxy$ + $y \times y \times x$ $yxxyxxx$

Now, $x y$ $xy$ or $y x$ $yx$ in the above equation can be replaced by $5$ $5$ ( $y x$ $yx$ can also be replaced by $5$ $5$ because multiplication of numbers in either sequence will give the same answer. For eg: $2 \times 3 = 3 \times 2 = 6$ $2xx3=3xx2=6$ )

and then, the equation becomes: $5 x + 5 y$ $5x+5y$

Taking the common factor $5$ $5$ out, we get $5 (x + y)$ $5(x+y)$ ..........(1)

But $x + y = 5$ $x+y=5$
Putting this value of $x + y$ $x+y$ in the equation (1)

or, $5 \times 5 = 25$ $5 xx 5 = 25$

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Question #dc056

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