Question #c4eca

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Question #c4eca

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Answer 1 · 2017-12-28T09:31:25

Your answer is given below:

Explanation:

As, $g (x) = | x | - 2 and f (x) = | x |$ $g(x)=|x|-2andf(x)=|x|$
So, $g (x) = f (x) - 2$ $g(x)=f(x)-2$ ,it is the relation between $g (x) and f (x) (A n s .)$ $g(x)andf(x)color(blue)((Ans.))$
Again, $g (x) = | x - 4 | and f (x) = | x |$ $g(x)=|x-4|andf(x)=|x|$
Thus, $g (x) = | f (x) - 4 | (A n s .)$ $g(x)=|f(x)-4|color(red)((Ans.))$

Answer 2 · 2017-12-28T09:32:29

See explanation.

Explanation:

$g (x) = | x | - 2$ $g(x)=|x|-2$ vs. $f (x) = | x |$ $f(x)=|x|$
The $- 2$ $-2$ at the end of $g (x)$ $g(x)$ represents a vertical shift of 2 units down. Take the graph of $f (x)$ $f(x)$ and shift the whole thing down 2 units. This doesn't change the shape of the graph, just the location.

$g (x) = | x - 4 |$ $g(x)=|x-4|$ vs. $f (x) = | x |$ $f(x)=|x|$
The $- 4$ $-4$ inside the absolute value of $g (x)$ $g(x)$ represents a shift of 4 units to the right. Take the graph of $f (x)$ $f(x)$ and shift the whole thing 4 units to the right. Again, this doesn't change the shape, just changes the location.

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Question #c4eca

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