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Answer 1 · 2017-12-27T10:11:48

#dy/dx = x^2 - 6x + 5#

#dy/dx = 0# when #x^2 - 6x + 5 = 0#

or, #(x - 1)(x - 5) = 0#

i.e. the gradient is zero at #x = 1# and at #x = 5#

Using iterative methods on #y=(x^3)/3 -3x^2 +5x + 7# we get,

#x~~-0.88#, #x~~4.12# and #x~~5.77#

A sketch is shown

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