Question #b2872

We say that kelvin is equal to celsius + #273.15#.

#C=K+273.15#

Therefore,

#78C = (78 + 273.15)K = 351.15K#

1. For easier conversion, better to memorize these important data than the confusing temperature scales' conversion formula.
   #"Boiling/Freezing Point of water in " C=100^o"/"0^o#
   #"Boiling/Freezing Point of water in " K=373"/"273#
2. Set up the ratio and proportion to derive the conversion formula that can be formulated from the above data. Since these two scales have same size units; thus, 100 will be cancelled out.
   #(C-0)/(100-0)=(K-273)/(373-273)#
   #(C)/cancel((100))=(K-273)/cancel((100))#
   #color(red)(C=K-273 " from " K to C# #or"#
   #color(blue)(K=C+273 " from " C to K#
3. Since these two temperature scales have different zero points and that #0^oC# corresponds to #273K#; thus, conversion requires the addition of 273 to the #C# as derived.
4. Given the value in #C#, now find the temperature to be expressed in #K#. Knowing the previously derived formula, plug in the value of #color(red)(C=78^o)#; thus,
   #K=color(red)(C)+273#
   #K=78+273#
   #K=351#
5. Therefore #78^oC=351K#