How do you find the domain and range of $f (x) = \frac{\sqrt{x + 7}}{x^{2} + 7}$ $f(x)=sqrt (x+7)/(x^2+7)$ ?

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Answer 1 · 2017-12-25T04:38:19

domain $RR={x:x inRR,x>=(-7)}$ and range $RR={y:y inRR,y>=0}$

Suppose,y= $f(x)=sqrt(x+7)/(x^2+7)$
If $x<(-7),$ the mentioned equation can not be definable.

$sqrt(x+7)/(x^2+7)$ =indefinable,when $x<(-7.)$ $color(brown)[[As.sqrt(-x in RR)=(INDEFINABLE)]]$

Hence,Domain $RR=color(red){{x:x inRR,x>=(-7)}$

For the value of domain set,range of the equation will be greater than or equal $0$

*So,Range $RR=color(blue){{y:y inRR,y>=0}$ *

How do you find the domain and range of f(x)=sqrt (x+7)/(x^2+7)f(x)=√x+7x2+7f(x)=sqrt (x+7)/(x^2+7)?