Question #3a12a

1 Answer
Timber Lin
Dec 24, 2017

#x=pi/4k#

Explanation:

you can ignore the 7 because multiplying #csc(4x)# by a constant doesn't change whether a y-value exists at that point or not.

#csc(x)# is discontinuous when #x=pik#, where k is a constant.

that means #csc(4x)# is discontinuous when #4x=pik# or #x=pi/4k#

so the graph of #F(x)=7csc(4x)# is discontinuous when #x=pi/4k#

graph: graph{7csc(4x) [-7, 7, -11, 11]}

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