Question #c3ce8

1 Answer
Dec 19, 2017

It is a function.

Explanation:

Well, first remember that f(x) is a function when only one y value can match to a specific x value.

Ok. Let us now solve y this in terms of x, assuming y=f(x).

x=2y^2
x/2=y^2
sqrt (x/2)=y

We can see that there can only be one value of y for a specific value of x. Therefore, this is a function. (Limited, of course, since there can't be negative x values defined as a real number.