Question #7edac
1 Answer
Explanation:
Use this exponential decay equation:
Here
#y = 100(b)^(x/8) -># You divide#x# by#8# because the half-life is every#8# years
#y = 100(1/2)^(x/8)#
#y = 100(1/2)^(32/8) => y = "6.25 g remaining"#
Use this exponential decay equation:
Here
#y = 100(b)^(x/8) -># You divide#x# by#8# because the half-life is every#8# years
#y = 100(1/2)^(x/8)#
#y = 100(1/2)^(32/8) => y = "6.25 g remaining"#