How do you evaluate #(0.1246) ( - 3.72)#?

When you have two numbers that seemingly have no operation symbol between them, this usually means multiplication, as in this case.

Note that you are multiplying a positive number by a negative number. This means that the answer will be negative as well.

All you have to do now is multiply!

#0.1246*(-3.72)=-0.463512#

When multiplying two values, if the signs are the same then the answer is positive. If the signs are not the same then the answer is negative. So in this case the answer is negative.

Write as #-(0.1246 xx 3.72)#

If the decimals are giving you a problem you can use a sort of cheat.

Note that #0.1246" is the same as "1246xx1/10000#

Note that #3.72" is the same as "372xx1/100#

So we may write as: #-(372xx1/100xx1246xx1/10000)#

This is the same as: #-(372xx1246xx1/1000000)#
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We will deal with the negative and the #xx1/1000000 # at the end.

#1246xx300=373800#
#1246xxcolor(white)("d")70=color(white)("d")87220#
#ul(1246xxcolor(white)("dd")2=color(white)("dd")2492 larr" Add")#
#color(white)("dddddddddddd")463512#

Giving #-(463512xx1/1000000)#

#-0.463512#