Consider a bag with marbles, 3 blue marbles, 2 red marbles, and 5 green marbles. two marbles are drawn in sequence. what is the probability of taking a blue marble, replacing it, and then taking another blue marble ?

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Answer 1 · 2017-12-14T20:28:41

$\frac{9}{100}$ $9/100$

$P$ $P$ (Taking a blue marble first try) = $\frac{3}{10}$ $3/10$

$P$ $P$ (Taking a blue marble second try) = $\frac{3}{10}$ $3/10$

$P$ $P$ (Taking a blue marble first try) $\times$ $\times$ $P$ $P$ (Taking a blue marble second try) = $\frac{9}{100}$ $9/100$