How do you solve $x = 3 - x \sqrt{2}$ $x= 3- x \sqrt { 2}$ ?

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Answer 1 · 2017-12-14T00:28:24

$x = \frac{3}{1 + \sqrt{2}}$ $x=3/(1+sqrt2)$

Solving equations is the isolation of the variable:

Since we already have $x$ $x$ on the left side, leave it that way.

Add $x \sqrt{2}$ $xsqrt2$ to both sides to get $x + x \sqrt{2} = 3$ $x+xsqrt2=3$

The left hand side can be simplified by taking a factor of $x$ $x$ out:

$(1 + \sqrt{2}) x = 3$ $(1+sqrt2)x=3$

Now just divide both sides by $(1 + \sqrt{2})$ $(1+sqrt2)$

Therefore, $x = \frac{3}{1 + \sqrt{2}}$ $x=3/(1+sqrt2)$

How do you solve x=3−x√2x= 3- x \sqrt { 2}?