Question #8b77a

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Question #8b77a

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Answer 1 · 2017-12-12T18:04:09

611g

Explanation:

Number of mols of Mg = $\frac{mass (g)}{Relative Molecular Mass (g per mol)}$ $"mass (g)"/"Relative Molecular Mass (g per mol)"$ = $\frac{156}{24}$ $156/24$ = 6.5mols

Therefore, if we have 6.5mols of $M g$ $Mg$ as a reactant, we must have 6.5mols of $M g C l_{2}$ $MgCl_2$ as a product after the reaction.

We can rearrange the equation previously used to calculate the mass of 6.5mols of $M g C l_{2}$ $MgCl_2$ .

$mass (g) = Relative Molecular mass (g per mol) \cdot Number of mols$ $"mass (g)" = "Relative Molecular mass (g per mol)" * "Number of mols"$ = $94 \cdot 6.5$ $94*6.5$ = 611g

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