Question #3066e

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Question #3066e

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Answer 1 · 2017-12-10T19:58:00

$f = 5.65 \times 10^{- 14} Hz$ $f=5.65times10^-14" Hz"$

Explanation:

$v = f \cdot λ$ $v=f*lambda$
velocity = frequency $\times$ $times$ wavelength

So plug in the values you've been given and solve for the frequency:

$λ = 531 \times 10^{- 9} m - because it's nanometres$ $lambda=531 color(red)(times 10^-9)"m" - "because it's nanometres"$
$v = 3 \times 10^{8} {ms}^{- 1}$ $v = 3times10^8 " ms"^-1$ (approx. speed of light)

$3 \times 10^{8} = f \cdot 531 \times 10^{- 9}$ $3times10^8=f*531times10^-9$

$\frac{3 \times 10^{8}}{531 \times 10^{- 9}} = f$ $(3times10^8)/(531times10^-9)=f$

$f = 5.65 \times 10^{- 14} Hz$ $f=5.65times10^-14" Hz"$

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Question #3066e

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