Question #dc54e

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Question #dc54e

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Answer 1 · 2017-12-08T20:27:44

100 newspapers

Explanation:

You have to turn the confusing tangle of words into nice clear maths equations.

So, the first paper run is a flat rate of $15 p/w + $$ 0.02 \times no. of newspapers$ $$0.02 times "no. of newspapers"$ . This can be expressed as $R_{1} (run) = 0.02 n + 15$ $R_1"(run)"=0.02n+15$

The second paper run can be expressed as $R_{2} = 0.03 n + 14$ $R_2=0.03n+14$

Now look back at the question and work out what it's actually asking you to do: how many newspapers must he deliver to make the same amount of money he earns now?

So we need to solve for $n$ $n$ when $R_{1} = R_{2}$ $R_1=R_2$ :
$0.02 n + 15 = 0.03 n + 14$ $0.02n+15=0.03n+14$
$0.02 n + 1 = 0.03 n$ $0.02n+1=0.03n$
$1 = 0.01 n$ $1=0.01n$
$\frac{1}{0.01} = n$ $1/0.01=n$
$n = 100$ $n=100$

$:.$ Mike needs to deliver 100 newspapers before he gets the same amount of money.

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Another way to do this is to plot both equations and see where they intercept.

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