Determine all critical points for the function???? please help me $x^2-6x+7$

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Answer 1 · 2017-12-07T04:24:57

You'll have one 'C' value at x = 3

Assuming $y=x^2-6x+7$ , first start by taking the first derivative.

$dy/dx = 2x - 6 + 0$ $rarr$ $dy/dx = 2x-6$

Next set the first derivative equal to zero, as you'll find critical points when $dy/dx=0 or dy/dx= DNE$

$2x - 6 = 0 rarr 2x = 6 rarr x = 3$

Solving the first derivative for when it is 0 yields a x value of 3 or in this case a 'C' value (critical point).

Determine all critical points for the function???? please help me x^2-6x+7x^2-6x+7