Determine all critical points for the function???? please help me #x^2-6x+7#

1 Answer
Dillin N.
Dec 7, 2017

You'll have one 'C' value at x = 3

Explanation:

Assuming #y=x^2-6x+7#, first start by taking the first derivative.

#dy/dx = 2x - 6 + 0# #rarr# #dy/dx = 2x-6#

Next set the first derivative equal to zero, as you'll find critical points when #dy/dx=0 or dy/dx= DNE#

#2x - 6 = 0 rarr 2x = 6 rarr x = 3#

Solving the first derivative for when it is 0 yields a x value of 3 or in this case a 'C' value (critical point).

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