Question #7c1f2

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Question #7c1f2

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Answer 1 · 2017-12-07T01:23:36

$x=-3$

$y=1$

Explanation:

We don’t need to manipulate this system of equations, the $y$ terms are already opposites, meaning they will cancel out—eliminate—when the equations are added.

So just add the equations:

$\quad2x+cancel(y)=-5$
+ $3x-cancel(y)=-10$
._________

$\implies 5x=-15$

$therefore x=-3$

Plug $x$ into one equation to solve for $y$ :

$2x+y=-5$

$\implies 2(-3)+y=-5$

$\implies -6+y=-5$

$\therefore y=1$

Check the answers by plugging both into an equation:

$3x-y=-10$

$\implies 3(-3)-1=-10$

$\implies -9-1=-10$

$implies -10=-10$

So the answer is correct.

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Question #7c1f2

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