If (k, 5) lies on the line with equation 3x-y =-8, what is the value of k?

Show work and explain please

2 Answers
Dec 4, 2017

k=-1k=1

Explanation:

"since "(k,5)" lies on the line then it satisfies the equation"since (k,5) lies on the line then it satisfies the equation

"substitute into the equation and solve for k"substitute into the equation and solve for k

"that is "x=k" and "y=5that is x=k and y=5

rArr3k-5=-83k5=8

"add 5 to both sides"add 5 to both sides

3kcancel(-5)cancel(+5)=-8+5

rArr3k=-3

"divide both sides by 3"

(cancel(3) k)/cancel(3)=(-3)/3

rArrk=-1

Dec 4, 2017

k=-1

Explanation:

First, you need to make the equation 3x-y=-8 to the form y=mx+b

3x-y=-8

-y=-8-3x
y=(-8-3x)/-1
y=8+3x

Now, there are multiple ways you could solve this:

First way is to plug in 5 as the y value in this equation and solve for x.
y=8+3x
5=8+3x
-3=3x
-1=x

Second way is to graph this and find out.
The graph should look like this:

graph{8+3x [-10, 10, -5, 5]}
Im portant things ot remember: 8 is the y-intercept with the slope 3/1

We see that when y=5, the slope intersects at the point (-1,5).