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A car traveling at 60 mph has how much more energy than a car going at 20 mph?

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Multifunction · Darshan Senthil

Dec 4, 2017

9 times the Kinetic Energy

Explanation:

Kinetic energy $(K E)$ $(KE)$ = $0.5 m v^{2}$ $0.5mv^2$

..where $m$ $m$ = mass, and $v$ $v$ = velocity.

So at 20 mph, $K E = 0.5 m {(20)}^{2} = 200 m$ $KE = 0.5m(20)^2 = 200m$

And at 60 mph, $K E = 0.5 m {(60)}^{2} = 1800 m$ $KE = 0.5m(60)^2 = 1800m$

Note that $m$ $m$ = mass, and not meters!

So $\frac{1800 m}{200 m} = 9$ $(1800m)/(200m) = 9$ times the Kinetic Energy.

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