If $(x/3 +1, y - 2/3) = (5/3, 1/3)$ , what is the values of $x$ and $y$ ?

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Answer 1 · 2017-12-03T01:58:16

$x=2\quad,\quad y=3$

This can be broken up into two equations:

$\frac{x}{3}+1=\frac{5}{3}$

$y-\frac{2}{3}=\frac{1}[3}$

Solving the first one:

$\frac{x}{3}=\frac{2}{3}$

$\implies x=3\cdot\frac{2}[3}$

$\implies x=2$

Solving the second one:

$y=\frac{2}{3}+\frac{1}{3}$

$\implies y=3$

If (x/3 +1, y - 2/3) = (5/3, 1/3)(x/3 +1, y - 2/3) = (5/3, 1/3), what is the values of xx and yy?