How do you use end behavior, zeros, y intercepts to sketch the graph of #g(x)=(x+1)(x-2)^2(x-4)#?
1 Answer
graph{(x+1)(x-2)^2(x-4) [-10, 10, -5, 5]}
Explanation:
This is a quartic function. The equation has degree 4, so it is an even- degree polynomial.
The leading coefficient is positive, so as
In order to solve for the
The constant term is -16, so the coordinate of the
The zeroes of the function are the
The zero -1 has multiplicity 1, so the graph crosses the
The zero 2 has multiplicity 2, so the graph just touches the
The zero 4 has multiplicity 1, so the graph crosses the
