What is the volume of a sample of NaOH solution that contains 154 grams of NaOH and has a concentration of 0.55 M?

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Answer 1 · 2017-11-27T19:43:21

7000 #cm^3#

First we need to calculate the number of moles of NaOH in 154g. You do this using the following equation:

mol = mass / Mr

where mol = number of moles; mass = weight in grams; Mr = molecular weight

The Mr of NaOH can be calculated using the atomic weights (Ar) of sodium, oxygen, and hydrogen. These can be found on the periodic table.

Ar O = 15.999 #gmol^-1#
Ar Na = 22.990 #gmol^-1#
Ar H = 1.008 #gmol^-1#

Adding these all together you get the Mr of NaOH:
Mr NaOH = 39.99 #gmol^-1#

Then you substitute this into the equation to calculate the number of moles of NaOH:

no. mol NaOH = 154 g / 39.99 #gmol^-1#
no. mol NaOH = 3.85 mol

To calculate the volume you use the following equation:

v = n/c

where c = concentration; n = no. of moles; v = volume

You substitute in the moles of NaOH that you calculated before, and the concentration of the solution 0.55 M (M = #moldm^-3#)

v = 3.85 mol / 0.55 #moldm^-3#
v = 7 #dm^3# or 7000 #cm^3#