How do you simplify $\frac{13}{\sqrt[7]{y^{2}}}$ $\frac { 13} { \root[ 7] { y ^ { 2} } }$ ?

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How do you simplify $\frac{13}{\sqrt[7]{y^{2}}}$ $\frac { 13} { \root[ 7] { y ^ { 2} } }$ ?

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Answer 1 · 2017-11-26T21:13:53

$\frac{13 \sqrt[7]{y^{5}}}{y}$ $(13root[7] (y^5))/y$

Explanation:

We will express $\sqrt[7]{y^{2}}$ $root[7] (y^2$ as $y^{\frac{2}{7}}$ $y^(2/7)$ .
In order to make $y$ $y$ to be in an integral exponent, we need to multiply $y^{\frac{2}{7}}$ $y^(2/7)$ by $y^{\frac{5}{7}}$ $y^(5/7)$ to get $y^{1}$ $y^1$ .
Therefore, we multiply the fraction by $\frac{y^{\frac{5}{7}}}{y^{\frac{5}{7}}}$ $y^(5/7)/y^(5/7)$ to get $\frac{13 y^{\frac{5}{7}}}{y}$ $(13y^(5/7))/(y)$
Instead of writing $y$ $y$ raised to a fractional exponent, we use roots.

Therefore, the answer is $\frac{13 \sqrt[7]{y^{5}}}{y}$ $(13root[7] (y^5))/y$

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How do you simplify $\frac{13}{\sqrt[7]{y^{2}}}$ $\frac { 13} { \root[ 7] { y ^ { 2} } }$ ?

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How do you simplify \frac { 13} { \root[ 7] { y ^ { 2} } }137√y2\frac { 13} { \root[ 7] { y ^ { 2} } }?

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How do you simplify $\frac{13}{\sqrt[7]{y^{2}}}$ $\frac { 13} { \root[ 7] { y ^ { 2} } }$ ?