How do you solve $\root[ 3] { x - 6} + 6= - 4$ ?

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Answer 1 · 2017-11-26T20:41:56

$x=-994$

$\root(3)(x-6)+6=-4$

Subtract $6$ from both sides:

$\root(color(red)(3))(x-6)=-10$

Cube both sides to cancel out the cube root:

$(\root(color(red)(3))(x-6))^color(red)(3)=(-10)^color(red)(3)$

Simplifying:

$x-6=-1000$

$\rightarrow x=-944$

How do you solve \root[ 3] { x - 6} + 6= - 4\root[ 3] { x - 6} + 6= - 4?