Question #817b7

2 Answers
Nov 26, 2017

Length=#34units# and width#=39units#

Explanation:

Let the width of rectangle be #x# units.
Then its length will be #(x-5)#units.

Perimeter of rectangle#=146#

#or, 2(l+b)=146#

#or, (x-5+x)=73#

#or, x=78/2=39#

So , the width of the rectangle #=x=39# and the length#=x-5=39-5=34#

Nov 26, 2017

#"length "=47" and width "=26#

Explanation:

#"the perimeter of a rectangle is"#

#• " perimeter "=2l+2w#

#"where l is the length and w the width"#

#"let the width "=x#

#rArr"length "=2x-5larr"5 less than twice the width"#

#rArr2(2x-5)+2x=146larrcolor(blue)"solve for x"#

#rArr2x-10+2x=146#

#rArr4x-10=146#

#"add 10 to both sides"#

#4xcancel(-10)cancel(+10)=146+10#

#rArr4x=156#

#"divide both sides by 4"#

#(cancel(4) x)/cancel(4)=156/4#

#rArrx=26#

#"width "=x=26#

#"length "=(2xx26)-5=52-5=47#

#color(blue)"As a check"#

#(2xx47)+(2xx26)=94+52=146larr" True"#