Question #2ed49

Question

702 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-26T11:24:02

#alpha=1/2#
#beta=-1/3#
#gamma=1#

let #a=1/alpha# , #b=1/beta# , #c=1/gamma#

#=>#

#4a-b+c=12 => c=12+b-4a#
#2a+2b+3c=1#
#5a-2b+6c=22#

#=>#

#2a+2b+3*(12+b-4a)=1#
#5a-2b+6*(12+b-4a)=22#

#=>#

#2a+2b+36+3b-12a=1#
#5a-2b+72+6b-24a=22#

#=>#

#-10a+5b=-35#
#-19a+4b=-50#

#=>#

#-2a+b=-7 => b=-7+2a#
#-19a+4b=-50#

#=>#

#-19a+4*(-7+2a)=-50#

#=>#

#-19a-28+8a=-50#

#=>#

#-11a=-22 => a=2#

#=>#

# b=-7+2*(2)=-3#

#=>#

# c=12+(-3)-4*(2)=1#

#=>#

#2=1/alpha => alpha=1/2#
#-3=1/beta => beta=-1/3#
#1=1/gamma => gamma=1#

check:

#4/(1/2)-1/(-1/3)+1=8+3+1=12#

#2/(1/2)+2/(-1/3)+3/1=4-6+3=1#

#5/(1/2)-2/(-1/3)+6/1=10+6+6=22#