How do you solve $(x ^ { 3} + 5x ^ { 2} \cdot 6x - 2) \div ( x - 1)$ ?

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Answer 1 · 2017-11-26T03:52:53

$31x^2+31x+31+\frac{29}{x-1}$

First, we can simplifying the terms of the dividend:

$(x^3+5x^2\cdot 6x-2)\div(x-1)$

$=(x^3+30x^3-2)\div(x-1)$

$=(31x^3-2)\div(x-1)$

Since the divisor is in the form $(x-c)$ , we can use synthetic division:

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How do you solve (x ^ { 3} + 5x ^ { 2} \cdot 6x - 2) \div ( x - 1)(x ^ { 3} + 5x ^ { 2} \cdot 6x - 2) \div ( x - 1)?