Question #c1210

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Answer 1 · 2017-11-25T23:23:15

see explanation

Let's start with the RHS.

Addition of two logs means that you multiply them:

#log(x+1)log(x-5) = log((x-7)(x-3))#

Next cancel out the logs:

#(x+1)(x-5) = (x-7)(x-3)#

Simplify equation to calculate solution:

#(x^2-4x-5)-(x^2-10x+21)=0#

#cancel(x^2) -4x-5 - cancel(x^2) +10x-21=0#

#6x - 26=0#

#6x = 26#

#x = 26/6 or 4.333 sf#