Question #33b66

1 Answer
Manasvini Nittala
Nov 25, 2017

the solution is I=-cos(logx)+c

Explanation:

let, I=intsin(logx)/xdx->(1)
let us use substitution method
let, t=logx->(2) then dt=1/xdx->(3) substitute (2) and (3) in (1)
we get,I=intsintdtrArr-cost+crArr-cos(logx)+c
:.I=-cos(logx)+c

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