What is the standard form of #y=x^2(x+4)(x-5) -x^2#? Algebra Polynomials and Factoring Polynomials in Standard Form 1 Answer Tamir E. Nov 23, 2017 #y=x^2(x^2-x-21)# or #y=x^4-x^3-21x^2# Explanation: #y=x^2(x+4)(x-5)-x^2=# #=x^2[(x+4)(x-5)-1]=# #=x^2[x^2-x-20-1]=# #=x^2[x^2-x-21]=# #=x^4-x^3-21x^2# Answer link Related questions What is a Polynomial? How do you rewrite a polynomial in standard form? How do you determine the degree of a polynomial? What is a coefficient of a term? Is #x^2+3x^{\frac{1}{2}}# a polynomial? How do you express #-16+5f^8-7f^3# in standard form? What is the degree of #16x^2y^3-3xy^5-2x^3y^2+2xy-7x^2y^3+2x^3y^2#? What is the degree of the polynomial #x^4-3x^3y^2+8x-12#? What is the difference between a monomial, binomial and polynomial? How do you write #y = 2/3x + 5# in standard form? See all questions in Polynomials in Standard Form Impact of this question 1299 views around the world You can reuse this answer Creative Commons License