Question #457c7?

Let Jason have 12x $ and Wilson 13x$. After spending 63$ , he will have 13x-63 $ with him.

The situation now is that 12x $ is 3 times of (13x-63)$. Putting it in equation form, it would be
12x= 3* (13x-63) #-># 12x= 39x-189#-># 27x=189 #-># x=7

This means that at the beginning Jason had 84$ and Wilson had #91$
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#color(blue)("Setting up the given information")#

Let Jason's original money be represented by #j#
Let Wilson's original money be represented by #w#

Using ratio in fraction format

Then initial condition

#j/w=12/13 color(white)("ddd")->color(white)("ddd") j=12/13w" ".........Equation(1)#

But Wilson spent $63 changing the ratio to:

#j/(w-63)=3/1color(white)("ddd")->color(white)("ddd")j=3w-189" "..Equation(2)#

Using #Eqn(2)# substitute for #j" in "Eqn(1)#

#color(green)(color(red)(j) =12/13wcolor(white)("ddd")->color(white)("ddd")color(red)(3w-189)=12/13w ) #

#color(green)(color(white)("dddddddddd")->color(white)("ddd")27/13w=189)#

#color(white)("dddddddddd")->color(white)("dddddd")color(blue)(w=$91)#
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Substitute for #w# in #Equation(1)# to find Jason's original sum of money.