How do you solve $37 = 8 (x + 2) + 5 x$ $37= 8( x + 2) + 5x$ ?

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Answer 1 · 2017-11-20T04:43:34

$x = \frac{21}{13}$ $x=21/13$

Okay, let's expand this:

$37 = 8 x + 16 + 5 x$ $37=8x+16+5x$

$37 = 13 x + 16$ $37=13x+16$

$37 - 16 = 13 x$ $37-16=13x$

$21 = 13 x$ $21=13x$

$x = \frac{21}{13}$ $x=21/13$

Now, let's check our work by plugging $x$ $x$ back into the equation:

$37 = 8 (\frac{21}{13} + 2) + 5 \cdot \frac{21}{13}$ $37=8(21/13+2)+5*21/13$

$37 = \frac{168}{13} + 16 + \frac{105}{13}$ $37=168/13+16+105/13$

$37 - 16 = \frac{273}{13}$ $37-16=273/13$

$21 \cdot 13 = 273$ $21*13=273$

$273 = 273$ $273=273$

It looks like our solution is correct and makes sense! Hope this helps!

How do you solve 37=8(x+2)+5x37= 8( x + 2) + 5x?