How do you solve this system of equations: $2 (4 x + 5) = y + 4 x and 1 = - 2 (x - y)$ $2( 4x + 5) = y + 4x and 1= - 2( x - y )$ ?

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How do you solve this system of equations: $2 (4 x + 5) = y + 4 x and 1 = - 2 (x - y)$ $2( 4x + 5) = y + 4x and 1= - 2( x - y )$ ?

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Answer 1 · 2017-11-19T02:58:53

$x = - \frac{19}{6}$ $x=-19/6$ and $y = 2 \frac{2}{3}$ $y=2 2/3$

Explanation:

Make one of the equations in terms of the other:

$y = 2 (4 x + 5) - 4 x$ $y=2(4x+5)-4x$
$y = 4 x + 10$ $y=4x+10$

Now substitute into the other equation:

$1 = - 2 (x - (4 x + 10))$ $1= -2(x-(4x+10))$
$1 = - 2 (x - 4 x - 10)$ $1=-2(x-4x-10)$
$1 = - 2 (- 3 x - 10)$ $1=-2(-3x-10)$
$1 = 6 x + 20$ $1=6x+20$
$- 19 = 6 x$ $-19=6x$
$x = - \frac{19}{6}$ $x=-19/6$

Now put this value for $x$ $x$ into the other equation:

$y = 4 (- \frac{19}{6}) + 10$ $y=4(-19/6)+10$
$y = - 12 \frac{2}{3} + 10$ $y=-12 2/3 +10$
$y = 2 \frac{2}{3}$ $y=2 2/3$

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How do you solve this system of equations: $2 (4 x + 5) = y + 4 x and 1 = - 2 (x - y)$ $2( 4x + 5) = y + 4x and 1= - 2( x - y )$ ?

1 Answer

Explanation:

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How do you solve this system of equations: 2(4x+5)=y+4xand1=−2(x−y)2( 4x + 5) = y + 4x and 1= - 2( x - y )?

1 Answer

Explanation:

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How do you solve this system of equations: $2 (4 x + 5) = y + 4 x and 1 = - 2 (x - y)$ $2( 4x + 5) = y + 4x and 1= - 2( x - y )$ ?