How do you solve #\frac { 18} { x - 2} - \frac { 4} { x - 1} = \frac { 4} { x ^ { 2} - 3x + 2}#?

1 Answer
Ori Kiko
Nov 16, 2017

It has no solution.

Explanation:

First of all we do the gcf between #(x-2)# and #(x-1)#, that's found by multiplying them with each other,
#(x-2)(x-1)=x^2-3x+2#

so now we have this:
#(18-4)/(x^2-3x+2)=4/(x^2-3x+2)#

we can simplify the divisors:
#(18-4)/cancel(x^2-3x+2)=4/cancel(x^2-3x+2)#

#18-4=4#

As you can see, there's no x in the equation, what means that there's no solution to this equation.

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