Solve this system of equations: 4x-2y=64x−2y=6, 3x+y=23x+y=2?

2 Answers
kxoraxe
Nov 11, 2017

See below

Explanation:

Assuming second equation is 4x-2y=64x−2y=6
Using substitution:

Isolate yy in first equation:
3x+y=23x+y=2
y=2-3xy=2−3x

Sub y=2-3xy=2−3x into second equation:
4x-2(2-3x)=64x−2(2−3x)=6
4x-4+6x=64x−4+6x=6
10x-4=610x−4=6
10x=6+410x=6+4
10x=1010x=10
x=1x=1

Sub x=1x=1 into first equation:
3(1)+y=23(1)+y=2
3+y=23+y=2
y=2-3y=2−3
y=-1y=−1
:.POI=(1, -1)

Alternatively, graph both lines to find the point of intersection.

MathFact-orials.blogspot.com
Nov 12, 2017

Here's the graph:

Explanation:

graph{(3x+y-2)(4x-2y-6)=0}

Related questions
Impact of this question
3309 views around the world
You can reuse this answer
Creative Commons License