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Question #fb4e0

1 Answer

Nov 9, 2017

#z-4ln(z+4)+C#

Explanation:

#int (z*dz)/(z+4)#

#=int ((z+4-4)*dz)/(z+4)#

#=int ((z+4)*dz)/(z+4)#-#=int (4*dz)/(z+4)#

#=int dz#-#int (4*dz)/(z+4)#

#=z-4ln(z+4)+C#

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